9¤ë20¤é§ó·s
¬P´Á¤@ 7¸¹¤Î20¸¹¦P¾Ç ½Ð·Ç³Æ^¤å°ód³¥
¥ò¦³^¤å¤p´ú¥Í¦r10Ó ½Ð§Q¥Î¬ü¤k¼p©Ð¼s§i®É¶¡¶ë¤J¸£
¬P´Á¤@¦¤W§èºX¥Jºò°O¤Å¿ð §_«hn§Û°êºXªk
¥H¤W¸ê°T¥Ñ16¸¹¤H¥J´£¨Ñ ¬O¤]
-------------------------------------------------------------------------------------------------------
~~½Ð¦U¦ì¦P§ÓÚ»§¹¦P§Û§¹³£¯dÓcm~~
¤£µM!!´N½ð¶i¶Â¦W³æ¤º~! ½Ð¤j+¦w¦u11cªº³W¯x
¥¤¥¤ªº!!¬°¤j+¥\½ÒµÛ·Q.¥»¤H©ó¹s±á1:10¬°¤j+¤W¶Çµª®×...¥H¤U//¦³«§5©ú½Ð¦^ÂÐ~Í·|¬°¤j+¸Ñµª
¤Æ¥\(§ð²¤)ÃD¥Øin_p.79
°ÝÃD(1)¨t¨D¶q¿@«×(©j¨tc)
(1)¥ý¨D¦õÓm¥ý
M=P(±K«×)V(Åé¿n)W(½è¶q¤À¼Æ)
M=15%x025x1.1=41.25g
¤§«á¨D®IÓn(ª«½èªº¶q)
n=m(½è¶q)/M=41.25/2+32+16x4=0.42mol
¦A¨D®IÓc´N·dÕi
c=n/v=0.42/0.25=1.68mol/L
°ÝÃD(2)¨DH2ªºÅé¿n(V)
¥ý¦C±ø¤èµ{
H2SO4+Fe=FeSO4+H2(¤W¤É)
1 22.4(¼Ð·Ç)
0.25x1.68 V
¦n©úÚ»¥XÂI¨D°Õ±¾!!!§Y
V=0.25x1.68x22.4/1=9.4L
°ÝÃD(3)
¦n²³æ¤S¨t¨DC_GA!
¥Îµf¤W±GA¤½¦¡
C=n/V=0.42/0.4=1.05mlo/L
¦pªG5¨tËÝ©ú !!«ØÄ³Ú»¤UP.71&72ÃD¥Ø³£¦n¦ü¤U
µª®×¥Ñ«Óªá´£¨Ñ
|