a (i)
當n=k+1
5k+1 -1
=5 (5k) -1
=5(4M+1)-1
=5 (4M) + 4
=4 (5M+1)
(ii)
4k+1-1
=4(4k) -1
=4(3M+1)-1
=4(3M)+3
=3(4M+1)
b.
3(5k+1)+4k+2-7
=15 (5k)+16(4k)-7
=15(4M+1)+16(3M+1)-7 ) <---a部已證 5k =4M+1 & 4k =3M+1
=60M+15+48M+16-7
=108M+24
=12(9M+2)