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2009 年 5 月 30 日  星期六   晴天


導函數(Derivative) 分類: Calculus

我好耐冇打微積分既文章,今次我地會講下導函數(derivative)

當我地寫S=f(t)既時候,我地令位置因時間而定,所以位置係時間既因變數,時間係自變數.

速度係單位時間入面位置既變率,所以我地明白速度係:

v=\lim_{\Delta t\to 0}\frac{\Delta S}{\Delta t}

 

等我地諗下函數既定義:y=f(x),y係因變數,x係自變數.

y對x既變率=\lim_{\Delta x\to 0}\frac{\Delta y}{\Delta x}

 

我地用\frac{dy}{dx}表示 \lim_{\Delta x\to 0}\frac{\Delta y}{\Delta x}會方便得多!

\frac{dy}{dx}係對於x值既y值導函數.

點樣計算呢,先例一啲公式:

1)\frac{d}{dx}x^n=nx^{n-1}

2)\frac{d}{dx}(u \pm v)=\frac{d}{dx}u \pm \frac{d}{dx}v

3)\frac{d}{dx}(uv)=u\frac{d}{dx}v+v\frac{d}{dx}u

4)\frac{d}{dx}(\frac{u}{v})=\frac{v\frac{d}{dx}u-u\frac{d}{dx}v}{v^2}

 

5)\frac{d}{dx}\omega (u)=\frac{d\omega}{du}\frac{du}{dx}   (呢個係鎖鏈律(chain rule))

6)\frac{d}{dx}ln(x)=\frac{1}{x}

7)\frac{d}{dx}e^x=e^x

 

8)\frac{d}{dx}a^x=a^xlna

 

9)\frac{d}{dx}\sin{x}=\cos{x}

10)\frac{d}{dx}\cos{x}=-\sin{x}

11)\frac{d}{dx}\tan{x}=\sec^2{x}

 

12)\frac{d}{dx}\sec{x}=\sec{x}\tan{x}

13)\frac{d}{dx}\cot{x}=-\csc^2{x}

 

14)\frac{d}{dx}\sin^{-1}{x}=\frac{1}{\sqrt{1-x^2}}

 

15)\frac{d}{dx}\cos^{-1}{x}=-\frac{1}{\sqrt{1-x^2}}

 

16)\frac{d}{dx}\tan^{-1}{x}=\frac{1}{1+x^2}

 

17)\frac{d}{dx}\cot^{-1}{x}=-\frac{1}{1+x^2}

eg:

1)

\frac{d}{dx}\frac{\sqrt{x\sqrt{x^3}}}{x^2}

=\frac{1}{x^4}(x^2\frac{d}{dx}x^{\frac{1}{2}}x^{\frac{3}{4}}-x^{\frac{1}{2}}x^{\frac{3}{4}}\frac{d}{dx}x^2)..........................................(4)

=\frac{1}{x^4}\left[x^2(\frac{5}{4}x^{\frac{5}{4}-1})-x^{\frac{5}{4}}(2x)\right].........................................(1)

=\frac{5}{4}x^{-\frac{7}{4}}-2x^{\frac{9}{4}}

2)

\frac{d}{dx}x\sin{\frac{1}{x}}

=x\frac{d}{dx}\sin{\frac{1}{x}}+\sin{\frac{1}{x}}\frac{d}{dx}x.........................................(3)

=x\cos{\frac{1}{x}}\frac{d}{dx}\frac{1}{x}+\sin{\frac{1}{x}} .........................................(5)代u=1/x,x\frac{d}{du}\sin{u}\frac{du}{dx}+\sin{\frac{1}{x}}

=-\frac{1}{x}\cos{\frac{1}{x}}+\sin{\frac{1}{x}}

3)

\frac{d}{dx}e^{x^x}

=\frac{d}{du}e^u\frac{d}{dx}x^x.........................................(5) (代u=xx )

=e^{x^x}x\times x^{x-1}

=e^{x^x}x^x

Exercise:

1)

Find  \frac{d^2}{dx^2}5^x                                (多重微分,\frac{d^2y}{dx^2}=\frac{d}{dx}\left(\frac{dy}{dx}\right))

2)

If   

\frac{dy}{dx}=3x^{\frac{2}{5}}+5,                           (遲下積分(integral)個到會討論,試下用自己既方法逆番過黎做)

find y.

3)

If \tan^{-1}{\frac{x}{y}}+ln\sqrt{x^2+y^2}=0,

show that  \frac{dy}{dx}=\frac{x+y}{x-y}